Skip to main content

Particle Accelerators, Radioisotopes, Antimatter, and Medicine

In my last blog, I mentioned I would include four topics in this weeks blog:
First, my plan for this blog. Second, the tracers for PET scans, in particular fluorine-18 tracers Third my answer to my prompt from last week Forth, a new prompt. I will do these topics in this order.


I am starting my next semester on the 16th of January. My courses will be Biology 196, Environmental Science 206, Math 286, and Chemistry 402.
After todays blog, my plan is to post every week during the weekend (somewhere from Friday to Sunday) with a real world application of a topic from one of these courses for the next 17 weeks, starting next week (the weekend prior to the beginning of the semester). It is likely that I will post later in the weekend, but early-weekend posts are possible.


Now, as promised, the tracers used for PET scans. PET scans are positron emission tomography, which makes a three-dimensional mapping of the functional processes of one aspect of the body, typically the brain. It takes advantage of the pair of gamma rays observed from the emission of positrons from a compound containing a radioisotope.
As a side note, positrons are antimatter. They are anti-electron particles, which, when they collide with electrons, completely annihilate to form energy in the form of the previously mentioned gamma-ray pair. This alone is not particularly harmful, and it can be easily seen when we apply the most famous equation in the world; Einsteins' . When we plug in the mass for an electron and a positron (both having the same mass of 9.11*10^(-31) kg), we get E=8.8188*10^(-14) Joules or 1.96*10^(-17) Calories. We breathe more energy than that with every breath, so it's not really enough to do any damage at all.
The radioisotope commonly used for the tracer for PET scans is fluorine-18. The main reason for this is a timing issue. All radioisotopes which could theoretically be used for a tracer have half-lives. This is a term used for all radioactive atoms, which is the time it takes for half of the materials to radioactively decay. It is an exponential decay curve, which means after the first half-life, half of the radioactive material is remaining; after two half-lives, a quarter is remaining; after three half-lives, one-eighth is remaining and so on. Of all of the radioisotopes viable for PET scan tracers, Fluorine-18 has the longest half-life, making it's use the best for time purposes.
Since fluorine-18 is a radioisotope – and therefore has a half-life and decays – it cannot be stockpiled. So it has to be created via a cyclotron, which is a small particle accelerator. Think of a very scaled down version of the Large Hadron Collider, used not for destroying matter for study, but rather making matter for a practical purpose, matter which is normally not readily available for use. Fluorine-18 is created by bombarding a proton against an Oxygen-18 labeled water molecule, which can only be done in these small scale accelerators.
It used to be that we were restricted by old school reactions to form aryl fluorides suitable for human consumption that will not be chemically harmful, but as reported in the 04NOV2011 issue of Science Magazine, there has been significant research to develop an reaction which will be more suitable for radiochemistry. These reactions are used to create the aryl fluorides which are then used to create the fluorocarbohydrates (carbohydrates with one of the hydrogens on the ring replaced by fluorine-18) used for the tracers.
For those of you who are unaware of what reactions are, this stands for Dimolecular Nucleophilic Substitution Reaction. The substitution part refers to reactions which one group of one molecule and one group from the other molecule switch molecules. The dimolecular part means the rate of the reaction is dependent on the concentration of both reactants. The nucleoplhilic part means that the “minor” reactant (the one that can be thrown away afterwards) is attracted to the nucleus of an atom as opposed to the electrons.
The major downfall of Fluorine-18 is that it's half-life is 110 minutes, which means it needs to be created, put into the final tracer state, put into the patient, and the PET scan completed relatively quickly. This is the reason why research of chemistry of fluorine-18 is being done; so as to lessen the time the reaction part takes away from the total process.
And the research shows a lot of success. The experiments seem to be highly repeatable and consistently procure high yields of aryl fluorides with fluorine-18. It looks good that pretty soon, this process will become the most common process to use for creating tracers for PET scans. Hopefully this will decrease the production cost of tracers, thusly decreasing the cost for the PET scan procedure for patients.


As far as my answer to last weeks prompts, with how my brain works, I have not completed it. I've begun it, but my realm of existence is pretty complex right now, and my brain works very scientifically meticulous, so I am far from complete with the prompt. I may have it finished by next week.
This weeks prompt is biochemical in nature. Think of a way you can improve your emotional state, your physical state, or how you view yourself through easily accessible biochemical processes, including (but not limited to) change in diet, alterations in breathing habits, increase in exercise, alteration of medication intake, etc. Think of all the ways in which you can improve your emotional state as stated above through means you have at your disposal. If you are confused on what I mean by biochemical means, I will refer you to my youtube videos on the Basics of Chemistry (The Basics of Chemistry 1 and The Basics of Chemistry 2). I hope that helps in this prompt.
Until next Friday, have a great week and DFTBA!

Take that as you will.
-K. “Alan” Eister Δαβ


References:
Research for F-18:
Periodical: Science Magazine
Issue 04NOV2011
Title: “A Fluoride-Derived Electrophilic Late-Stage Fluorination Reagent for PET Imaging”
Lead Author: Eunsung Lee
Other Authors:Adam S. Kamlet, David C Powers, Constanze N. Neumann, Gregory B. Boursalian, Takeru Furuya, Daniel C. Choi, Jacob M. Hooker, and Tobias Ritter.
Pages: 639-642
Videos for Prompt:

Comments

Popular posts from this blog

Basic Statistics Lecture #3: Normal, Binomial, and Poisson Distributions

As I have mentioned last time , the uniform continuous distribution is not the only form of continuous distribution in statistics.  As promised, here are the three most common continuous distribution types.  As a side note, all sampling distributions are relative to the algebraic mean. Normal Distribution: I think most people are familiar with the concept of a normal distribution.  If you've ever seen a bell curve, you've seen the normal distribution.  If you've begun from the first lecture of this lecture series, you've also seen the normal distribution. This type of distribution is where the data points follow a continuous curve, is non-uniform, has a mean (algebraic average) equal to the median (the exact middle value), falls from highest probability at the mean to (for all practical purposes) zero as the x-values approach $\pm \infty$, and therefor has equal number of data points to the left and to the right of the mean, and has the domain of $(\pm \i

Confidence Interval: Basic Statistics Lecture Series Lecture #11

You'll remember last time , I covered hypothesis testing of proportions and the time before that , hypothesis testing of a sample with a mean and standard deviation.  This time, I'll cover the concept of confidence intervals. Confidence intervals are of the form μ 1-α ∈ (a, b) 1-α , where a and b are two numbers such that a<b, α is the significance level as covered in hypothesis testing, and μ is the actual population mean (not the sample mean). This is a the statement of there being a [(1-α)*100]% probability that the true population mean will be somewhere between a and b.  The obvious question is "How do we find a and b?".  Here, I will describe the process. Step 1. Find the Fundamental Statistics The first thing we need to find the fundamental statistics , the mean, standard deviation, and the sample size.  The sample mean is typically referred to as the point estimate by most statistics text books.  This is because the point estimate of the populati

Basic Statistics Lecture #5: Baye's Theorem

As promised last time , I am going to cover Baye's Theorem. If Tree diagram is the common name for Bayes Theorem.  Recall that conditional probability is given by $P(A \mid B) = \frac{P(A \wedge B)}{P(B)}$.   For tree diagrams, let's say that we have events A, B 1 , B 2 , B 3 , … (the reason we have multiple B's is because they all are within the same family of events) such that the events in the family of B are mutually exclusive and the sum of the probabilities of the events in the family of B are equal to 1. Then we have $$P(B_i \mid A)= \frac{P(B_i)*P(A \mid B_i)}{\sum_{m=1}^{n}[P(B_m)*P(A \mid B_m)]}$$  What this means is reliant on the tree diagram. If we are only looking at the sub-items of A, this is what the tree diagram would look like. If J has a probability of 100%, and P(C) and P(D) are not 0, then when we are trying to find the probability of any of the B's being true given that A is true, we have to set the probability of A to be the entir